(2^x)+2(x+1)=28

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Solution for (2^x)+2(x+1)=28 equation: 



(2^x)+2(x+1)=28

We move all terms to the left:

(2^x)+2(x+1)-(28)=0

We multiply parentheses

2^x+2x+2-28=0

We add all the numbers together, and all the variables

2x+2^x-26=0

We move all terms containing x to the left, all other terms to the right

2x+2^x=26

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